Balance the following redox reactions by the ion-electron method:
$(a)$ $MnO_{4(aq)}^- + I_{(aq)}^- \to MnO_{2(s)} + I_{2(s)}$ (in basic solution)
$(b)$ $MnO_{4(aq)}^- + SO_{2(g)} \to Mn_{(aq)}^{2+} + HSO_{4(aq)}^-$ (in acidic solution)
$(c)$ $H_2O_{2(aq)} + Fe_{(aq)}^{2+} \to Fe_{(aq)}^{3+} + H_2O_{(l)}$ (in acidic solution)
$(d)$ $Cr_2O_7^{2-} + SO_{2(g)} \to Cr_{(aq)}^{3+} + SO_{4(aq)}^{2-}$ (in acidic solution)

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(N/A) $2MnO_{4(aq)}^- + I_{(aq)}^- + H_2O_{(l)} \to 2MnO_{2(s)} + I_{2(s)} + 2OH_{(aq)}^-$
$(b)$ $2MnO_{4(aq)}^- + 5SO_{2(g)} + 2H_2O_{(l)} \to 2Mn_{(aq)}^{2+} + 5HSO_{4(aq)}^- + H_{(aq)}^+$
$(c)$ $H_2O_{2(aq)} + 2Fe_{(aq)}^{2+} + 2H_{(aq)}^+ \to 2Fe_{(aq)}^{3+} + 2H_2O_{(l)}$
$(d)$ $Cr_2O_7^{2-} + 3SO_{2(g)} + 2H_{(aq)}^+ \to 2Cr_{(aq)}^{3+} + 3SO_{4(aq)}^{2-} + H_2O_{(l)}$

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